In the circuit shown in the figure, if both the lamps L 1 and L 2 are identical:
Text Solution
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Sol. Answer (B, C) If Z be the total impedance of the circuit then
Z –1 = (R L + j ω L) –1 + 
Since, Z is independent of supply frequency ω , we have 
(Z –1 ) = 0
This gives: R L + j ω L = 
+ j ω R C 
Equating real and imaginary parts separately, we have
R L = R C = 
Let I L and I C be the branch currents in the inductive and capacitive branches respectively. Then
= 
= 
Since, C and R L are constants, we have 
∝ ω .
This means as the frequency of the supply voltage is increased, I C will increase, and I L will decrease. So, the brightness of L 1 will increase and that of L 2 will decrease.
As regards, Since, 
= 
= 
we have from
= w CR L ; Ω = 
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